6 thoughts on “Homework H5.P – Sp26”

    1. Because P is constrained along the ground, and B is going to be moving straight up, and the sling is of length L is both cases, You can find the IC of the sling itself connecting B and P using the geometry at the two positions. You can force the angular velocity of the sling to agree with B’s velocity, then solving for P. You need to do some trig in both locations but it works out.

  1. If we have the velocity of B, is the following equation the correct way of solving for P? I have an I and J component for velocity for P, which doesn’t seem correct.

    V_P = V_B + omega x r_P/B

    1. Yes, your equation is fine, provided that you use omega_BP (an unknown). Your vector equation has two scalar components in terms of the unknowns of v_P (where the vector for v_P is along the ground) and omega_BP.

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