One thought on “HOMEWORK 19 – Fall 25”

  1. For this problem, I solved for the maximum weight of C using only the tension in the cable between D and C (Td). While I believe my answer (Wc = Tdsin60 = We^(Ms*2.618 rad)sin60) to be correct, the relation between the tensions in the cables supporting C does not match the tension in cable CE (Te) using the tension ratio equation. Doing this, I got Te = W*e^(Ms*1.571 rad), which is not equal to Td cos(theta) as the FBD for block C requires. However, some online reading suggests that the ratio T_L/T_s is less than or equal to e^(Ms*B), which would validate my answers; at this weight, the left drum is impending slipping while the right drum is not. Can someone confirm this inequality?

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