HOMEWORK 2 – Summer 25

Problem statements
Solution video – H2.A
Solution video – H2.B

DISCUSSION THREAD

HINTS:
Part a) – Write down the position vector from C to B: rCB. The unit vector  from C to B is found by uCB =rCB/|rCB|. From this, the force of cable CB acting on the mast is: FCB = FCB*uCB.
Part b) -Worked out in a similar way, with CB to be replaced by CA.
Part c) – Refer to the lecture book for determining the direction angles and direction cosines directly from a unit vector that has been written in component form.

Please post questions here on the homework, and take time to answer questions posted by others. You can learn both ways.

8 thoughts on “HOMEWORK 2 – Summer 25”

    1. To find the unit vector u_CA, you should use the equation: u_CA =r_CA/|r_CA|.
      Here, r_CA is the position vector, which can be expressed in terms of its magnitude |r_CA| and the angles θ and ϕ.
      When you substitute this into the equation, the magnitude in the numerator and denominator will cancel out, leaving the unit vector expressed purely in terms of the angles θ and ϕ.

  1. I am having trouble visualizing the angle components to figure out if my answer makes sense. I know you have to “move the origin” but how do I know which end of the vector to move the origin to and how do I figure it out from there? Thank you in advance

    1. You can try to take a look at the example video of Example 2.B.2 under Lecture examples solutions tab (as Henry posted) to visualize the direction angles.

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