Problem statements
Solution video - H5.A
Solution video - H5.B
DISCUSSION THREAD

Please post questions here on the homework, and take time to answer questions posted by others. You can learn both ways.
Problem statements
Solution video - H5.A
Solution video - H5.B
DISCUSSION THREAD
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Are we required to write the answer as a vector?
No I do not believe so Shivum. Since the question is asking for the tension in each cable, you wouldn't split it up into its components since you wouldn't use that to determine whether the tension exceeds the constraints of the material. Although you could get it in vector form, there's really no need for it and the professor left only the magnitudes in the examples he did in class (just don't forget to include the W term for each of them).
Hi, is anyone able to access the video solution for H5.A? I'm not able to view the video because it's private.
Yeah I also just attempted to access the video for the same problem and I got the same message saying it was private, only the instructor can make it public.
Could we use matrices (from linear algebra) to solve systems of equations as part of our work?
Yeah, we can use any method we want. The professor also said we can use our calculators to solve the system of equations in our homework problems (not in exams though).
Yes and it will probably save you a lot more time!
Is it preferable to show multiple free body diagrams or one free body diagram that consists of every aspect of my working or the model itslef.
I believe that you should have atleast one in your work but I think having more than will just help you answering (basically for your own sake )the question but not required if I am not mistaken.
For HW 5.A (the non-required question), a mass of W would mean your answer would be in terms of "g" as well right? Since weight is calculated based on mass and the gravitational constant "g"?
My answer was just in terms of the other variables. It makes sense for the answer to be in terms of g, but I just treated the weight as any other force vector.