# HOMEWORK H29.B

## 20 thoughts on “HOMEWORK H29.B”

1. Zach Mullen says:

Do the 2T and 3T torsional loadings both act on member 2?

I said 2T acts on member 1 and 3T acts on member 2, or their respective connectors.

2. Jennifer Leigh Smith says:

Is the tension of AB equal to zero or T. Can someone explain this?

1. Kaushal Kamal Jain says:

Its neither zero not T. You should draw the FBD of each component and the connectors and figure out the tension/compression in each component from that.

3. Samuel James Pike says:

I may be mistaken but can we not also find the torques in each of the components graphically by finding the moment about A then factoring in the other torques in a graph?

1. Rahul Maheswaran says:

I think you can do that too - You can be sure by doing it both ways and see if the answers match. It was simple arithmetic to find the Torque load in each component via equations, so you won't lose out on much.

2. Kaushal Kamal Jain says:

Yes, Samuel you can do that too.

4. Carolyn Ann Lo coco says:

Does sign matter when calculating the torque?

1. Zaid Basil Qubain says:

torque is vector quantity. Therefore, direction does matter. However, when using torque to calculate scaler quantities such shear force direction(sign) wont effect your final answer.

5. Zaid Basil Qubain says:

For the maximum is it just the maximum between all the sections after we calculated them separately.

1. Zach Mullen says:

Yeah, whichever member has the maximum shear stress is the maximum. Because all of the loading is concentrated at points at each end, the location would be the whole member.

This doesn't necessarily mean that the member with the highest torque has the highest shear stress though.

6. Laurel Brianne Norris says:

How do we show the torque load on each component? Is it just what M would be on the graph? I didn't see an example with this wording in lecture

1. Lancelot Yunsi Li says:

I think the torque load can be comparable to the "reaction" torque to the torque applied. You can use equilibrium equations to find each load after you divide the shaft into segments. Example 4 shows this pretty well, the problem just doesn't have the arrows drawn the same way as in the homework.

7. Mansha Sunil Chimnani says:

Is the sign based on the direction of the component or the connector?

1. Lancelot Yunsi Li says:

I'm pretty sure the sign of the torque is just the direction the vector is pointing (positive for left, and negative for right).