{"id":23560,"date":"2026-03-04T08:01:02","date_gmt":"2026-03-04T13:01:02","guid":{"rendered":"https:\/\/www.purdue.edu\/freeform\/me274\/?p=23560"},"modified":"2026-03-08T15:08:39","modified_gmt":"2026-03-08T19:08:39","slug":"homework-h4-k-sp26","status":"publish","type":"post","link":"https:\/\/www.purdue.edu\/freeform\/me274\/2026\/03\/04\/homework-h4-k-sp26\/","title":{"rendered":"Homework H4.K &#8211; Sp26"},"content":{"rendered":"<table style=\"width: 100%;border-collapse: collapse;background-color: #faf7f7\">\n<tbody>\n<tr>\n<td style=\"width: 100%\"><a href=\"https:\/\/www.purdue.edu\/freeform\/me274\/wp-content\/uploads\/sites\/15\/2023\/11\/collection_fspI-dragged-20.pdf\"><span style=\"font-size: 12pt\"><em><strong>Problem statement<\/strong><\/em><\/span><\/a><br \/>\n<a href=\"https:\/\/youtu.be\/3Rd-yTU8h2Q\"><span style=\"font-size: 12pt\"><em><strong>Solution video<\/strong><\/em><\/span><\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<hr \/>\n<p><em><strong><span style=\"font-size: 14pt\">DISCUSSION THREAD<\/span><\/strong><\/em><\/p>\n<div data-post-id=\"15473\" class=\"insert-page insert-page-15473 \"><p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-14480\" src=\"https:\/\/www.purdue.edu\/freeform\/me274\/wp-content\/uploads\/sites\/15\/2022\/05\/Screen-Shot-2022-05-15-at-4.16.46-PM-300x90.jpg\" alt=\"\" width=\"493\" height=\"148\" srcset=\"https:\/\/www.purdue.edu\/freeform\/me274\/wp-content\/uploads\/sites\/15\/2022\/05\/Screen-Shot-2022-05-15-at-4.16.46-PM-300x90.jpg 300w, https:\/\/www.purdue.edu\/freeform\/me274\/wp-content\/uploads\/sites\/15\/2022\/05\/Screen-Shot-2022-05-15-at-4.16.46-PM.jpg 755w\" sizes=\"auto, (max-width: 493px) 100vw, 493px\" \/><\/p>\n<p>Ask and answer questions here. You learn both ways.<\/p>\n<hr \/>\n<p><em><strong>DISCUSSION and HINTS<\/strong><\/em><\/p>\n<p>Initially Block A slides to the right along Block B which is traveling to the right. However, with friction acting between A and B, both A and B slow down. At some point, A instantaneously comes to rest, and the starts to move to the left. Once the speed of A to the left matches that of the speed of B to the left, the two stick and move together. You can see this in the animation that follows.<\/p>\n<p><em><strong><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" style=\"border: 1px solid #000000\" src=\"https:\/\/www.purdue.edu\/freeform\/me274\/wp-content\/uploads\/sites\/15\/2022\/05\/H4C_07.gif\" width=\"606\" height=\"419\" \/><\/strong><\/em><\/p>\n<p>Recall the following <span style=\"text-decoration: underline\"><em>f<\/em><em>our-step plan<\/em><\/span> outline in the lecture book and discussed in lecture:<\/p>\n<p><em><strong>Step 1: FBDs<\/strong><\/em><br \/>\nDraw <em><span style=\"text-decoration: underline\">single<\/span><\/em> free body diagram (FBD) for the entire system (A+B). Do NOT consider A and B in separate FBDs because you will need to deal with the friction force acting between A and B (which you do not know).<\/p>\n<p><em><strong>Step 2: Kinetics (linear impulse\/momentum)<\/strong><\/em><br \/>\nConsider all of the external forces that you included in your FBD above. If there are no external forces acting in the horizontal direction (x-direction) on your system, the linear momentum in the x-direction is conserved.<\/p>\n<p><em><strong>Step 3: Kinematics<\/strong><\/em><br \/>\nAs described above, A comes to rest with respect to B when v<sub>A<\/sub> = v<sub>B<\/sub>.<\/p>\n<p><em><strong>Step 4: Solve<\/strong><\/em><br \/>\nCombine your kinetics equation from Step 2 with your kinematics that you found in Step 3, and solve for the velocity of B.<\/p>\n<p><span style=\"text-decoration: underline\"><em>QUESTION<\/em><\/span>: Are you surprised that your answer for the final speed of B (and A) does not depend on the coefficient of friction acting between A and B? I was the first time that I worked the problem. \ud83d\ude42<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Problem statement Solution video DISCUSSION THREAD<\/p>\n","protected":false},"author":10,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"categories":[5],"tags":[],"class_list":["post-23560","post","type-post","status-publish","format-standard","hentry","category-chapter-4-homework"],"_links":{"self":[{"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/posts\/23560","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/users\/10"}],"replies":[{"embeddable":true,"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/comments?post=23560"}],"version-history":[{"count":3,"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/posts\/23560\/revisions"}],"predecessor-version":[{"id":24255,"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/posts\/23560\/revisions\/24255"}],"wp:attachment":[{"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/media?parent=23560"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/categories?post=23560"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/tags?post=23560"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}