{"id":23313,"date":"2026-01-14T16:01:25","date_gmt":"2026-01-14T21:01:25","guid":{"rendered":"https:\/\/www.purdue.edu\/freeform\/me274\/?p=23313"},"modified":"2026-01-19T15:24:58","modified_gmt":"2026-01-19T20:24:58","slug":"homework-h1-c-sp-26","status":"publish","type":"post","link":"https:\/\/www.purdue.edu\/freeform\/me274\/2026\/01\/14\/homework-h1-c-sp-26\/","title":{"rendered":"Homework H1.C &#8211; Sp 26"},"content":{"rendered":"<table style=\"width: 100%;border-collapse: collapse;background-color: #faf7f7\">\n<tbody>\n<tr>\n<td style=\"width: 100%\"><a href=\"https:\/\/www.purdue.edu\/freeform\/me274\/wp-content\/uploads\/sites\/15\/2026\/01\/Untitled-2.pdf\"><span style=\"font-size: 12pt\"><em><strong>Problem statement<\/strong><\/em><\/span><\/a><br \/>\n<span style=\"font-size: 12pt\"><em><strong><a href=\"https:\/\/www.youtube.com\/watch?v=-n1_7N_UH1g\">Solution video<\/a><br \/>\n<\/strong><\/em><\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<hr \/>\n<p><em><strong><span style=\"font-size: 14pt\">DISCUSSION THREAD<\/span><\/strong><\/em><\/p>\n<div data-post-id=\"13162\" class=\"insert-page insert-page-13162 \"><p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-13164 aligncenter\" src=\"https:\/\/www.purdue.edu\/freeform\/me274\/wp-content\/uploads\/sites\/15\/2022\/01\/Screen-Shot-2022-01-02-at-6.49.28-PM-300x261.jpg\" alt=\"\" width=\"209\" height=\"182\" srcset=\"https:\/\/www.purdue.edu\/freeform\/me274\/wp-content\/uploads\/sites\/15\/2022\/01\/Screen-Shot-2022-01-02-at-6.49.28-PM-300x261.jpg 300w, https:\/\/www.purdue.edu\/freeform\/me274\/wp-content\/uploads\/sites\/15\/2022\/01\/Screen-Shot-2022-01-02-at-6.49.28-PM.jpg 327w\" sizes=\"auto, (max-width: 209px) 100vw, 209px\" \/><\/p>\n<p><em><strong>Discussion and hints:<\/strong><\/em><\/p>\n<p>In this problem, we know both the magnitude and direction for each of the velocity and acceleration vectors for the center of mass G. We know that the unit tangent vector <em><strong>e<\/strong><sub>t<\/sub><\/em> is in the same direction as the velocity vector <em><strong>v<\/strong><sub>G<\/sub><\/em>. The unit normal vector <em><strong>e<\/strong><sub>n<\/sub><\/em> is perpendicular to <em><strong>e<\/strong><sub>t<\/sub><\/em>, and points &#8220;up and to the right&#8221; (do you know why?). Projecting the acceleration vector <em><strong>a<\/strong><sub>G<\/sub><\/em> onto the unit tangent and unit normal vectors gives us the information that we need to find the rate of change of speed and the radius of curvature of the path.<\/p>\n<p>Carefully watch the animation below of the motion of the aircraft. When the acceleration vector shown in <span style=\"color: #ff0000\"><em>RED<\/em><\/span> points &#8220;backward&#8221; from the direction of travel, the aircraft is slowing down; that is, the rate of change of speed is negative. Conversely, when the acceleration vector is &#8220;forward&#8221; of the direction of travel, the aircraft is increasing in speed with a positive rate of change of speed. If you follow this logic, you are on your way to understanding the usefulness of the results of the path description of kinematics!<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" style=\"border: 1px solid #000000\" src=\"https:\/\/www.purdue.edu\/freeform\/me274\/wp-content\/uploads\/sites\/15\/2022\/01\/H1A_21.gif\" width=\"531\" height=\"293\" \/><\/p>\n<hr \/>\n<p>Any questions??<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Problem statement Solution video DISCUSSION THREAD<\/p>\n","protected":false},"author":10,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"categories":[2],"tags":[],"class_list":["post-23313","post","type-post","status-publish","format-standard","hentry","category-chapter-1-homework"],"_links":{"self":[{"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/posts\/23313","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/users\/10"}],"replies":[{"embeddable":true,"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/comments?post=23313"}],"version-history":[{"count":3,"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/posts\/23313\/revisions"}],"predecessor-version":[{"id":23502,"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/posts\/23313\/revisions\/23502"}],"wp:attachment":[{"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/media?parent=23313"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/categories?post=23313"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.purdue.edu\/freeform\/me274\/wp-json\/wp\/v2\/tags?post=23313"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}