Problem statementSolution video |

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Problem statementSolution video |

**DISCUSSION THREAD**

We encourage you to interact with your colleagues here in conversations about this homework problem.

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For part B, can the instant center of member EG be at point G? I found the velocity of point E from the previous step and I know point G can only move in the Y direction so the intersection of the lines I drew are at point G.

Cameron: For an appropriate configuration of the mechanism, G could possibly be the IC of EG. In the configuration provided, however, that does not appear to be the situation. The path of E is a circular arc centered at point F. A perpendicular to the tangent of the path of E does not intersect the perpendicular to the path of G at point G. Therefore, G is not the IC of EG.

When I click on the link for the solution video, it says that nothing was found.